16x^2+126x+16=0

Solution for 16x^2+126x+16=0 equation:

16x^2+126x+16=0

a = 16; b = 126; c = +16;
Δ = b2-4ac
Δ = 1262-4·16·16
Δ = 14852
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14852}=\sqrt{4*3713}=\sqrt{4}*\sqrt{3713}=2\sqrt{3713}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-2\sqrt{3713}}{2*16}=\frac{-126-2\sqrt{3713}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+2\sqrt{3713}}{2*16}=\frac{-126+2\sqrt{3713}}{32}
$